Question

# In an oil drop experiment, the following charges (in arbitary units) were found on a series of oil droplets:2.30 $$\times$$ 10$$^{-15}$$, 6.90 $$\times$$ 10$$^{-15}$$, 1.38 $$\times$$ 10$$^{-14}$$5.75 $$\times$$ 10$$^{-15}$$, 3.45 $$\times$$ 10$$^{-15}$$, 1.96 $$\times$$ 10$$^{-14}$$The magnitude of charge on the electron (in the same unit) is:

A
1.15 × 1015
B
2.30 × 1015
C
0.575 × 1015
D
1.96 × 1015

Solution

## The correct option is A 1.15 $$\times$$ 10$$^{-15}$$In an oil drop experiment, the following charges(in arbitary units)were found on a series of oil droplets:2.30 $$\times$$ 10$$^{-15}$$, 6.90 $$\times$$ 10$$^{-15}$$, 1.38 $$\times$$ 10$$^{-14}$$5.75 $$\times$$ 10$$^{-15}$$, 3.45 $$\times$$ 10$$^{-15}$$, 1.96 $$\times$$ 10$$^{-14}$$The magnitude of charge on the electron(in the same unit) is 1.15 $$\times$$ 10$$^{-15}$$. The charges on the oil drop are the integral multiple of the charge on the electron which is. 1.15 $$\times$$ 10$$^{-15}$$. Thus, 2.30 $$\times$$ 10$$^{-15}$$ is an integral multiple of 1.15 $$\times$$ 10$$^{-15}$$. It is two times the charge on the electron. 5.75 $$\times$$ 10$$^{-15}$$ is an integral multiple of 1.15 $$\times$$ 10$$^{-15}$$. It is five times the charge on the electron.Chemistry

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