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Question

# In an orthogonal cutting test on mild steel, the following data were obtained Cutting speed : 40m/min Depth of cut : 0.3mm Total rake angle : +5o Chip thickness : 1.5mm Cutting force : 900N Thrust force : 450N Using Merchant's analysis, the friction angle during the machining will be

A
26.6o
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B
31.5o
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C
45o
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D
63.4o
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Solution

## The correct option is B 31.5oThe coefficient of friction μ=FN=Fcsinα+FTcosαFccosα−FTsinα =900sin5o+450cos5o900cos5o−450sin5o =526.72857.35=0.614 Friction angle ∴β=tan−1(μ)=31.5o

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