In any - ABC- prove that -acos B-cos C-1-bcos C-cos A-1- - cos A-cos B-1-0

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Projection Formula

In any Δ ABC,...

Question

$I n a n y Δ A B C, prove that : a (c o s B + c o s C - 1) + b (c o s C + c o s A - 1) + c (c o s A + c o s B - 1) = 0$

Open in App

Solution

Suggest Corrections

Similar questions

a (\cos B + \cos C - 1) + b (\cos C + \cos A - 1) + c (\cos A + \cos B - 1) = 0

a (\cos B + \cos C - 1) + b (\cos C + \cos A - 1) + c (\cos A + \cos B - 1) = 0

\frac{\cos A}{b \cos C + c \cos B} + \frac{\cos B}{c \cos A + a \cos C} + \frac{\cos C}{a \cos B + b \cos A} = \frac{a^{2} + b^{2} + c^{2}}{2 a b c}

\frac{cos A}{(c cos B + b cos C)} + \frac{cos B}{(a cos C + cos A)} + \frac{cos C}{(a cos B + b cos A)} = \frac{a^{2} + b^{2} + c}{2 a b c}

Δ A B C

cosA + cos B + cos C = 1 + 4 sin \frac{A}{2} sin \frac{B}{2} sin \frac{C}{2}

\frac{1 - cos A + cos B + cos C}{1 - cos C + cos A + cos B} = \frac{tan (A / 2)}{tan (C / 2)}

Join BYJU'S Learning Program