In Boolean algebra ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(A+¯B)⋅C will be equal to.
A
(¯A⋅B)+¯C
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B
(A⋅¯B)+C
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C
(A⋅B)⋅C
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D
(A+¯B)+C
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Solution
The correct option is A(¯A⋅B)+¯C ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(A+¯B)⋅C=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(A+¯B)+¯C (From De Morgan's theorem) =(¯A⋅¯B)+¯C (From De Morgan's theorem) =(¯A⋅B)+¯C.