Question

In both the cases, block & monkey are at the same horizontal level. In both the cases, monkey climbs the rope. In case-1 rope remains vertical & in case-2 rope swings during motion. $t_1\&t_2$ are times taken by monkeys to reach the pulley in case-1 & case-2 respectively. In both cases, monkey applies the same force on the rope.

• A. $t_1=t_2$
• B. $t_1<t_2$
• C. In case-2, block reaches the pulley earlier than monkey
• D. In case-1, monkey reaches the pulley earlier than block

Answer 1

Answer: (B), (C)

In case-2, block reaches the pulley earlier than monkey

Monkey & block both reach the pulley at the same time. Upward acceleration
$=\frac{F-mg}{m}$
Time taken by monkey to reach pulley in case-2 is more as compared to case-1.
Block will reach in the same time, but monkey have less acceleration in upward direction, as only a component of '$F$' helps monkey to reach pulley.
$t_1<t_2$ and in case-2, block reaches the pulley earlier than monkey.