Question

In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12 g of AgBr. What is the percentage of bromine in the compound?

• A. 68.08%
• B. 34.04%
• C. 42.1%
• D. 50%

Answer 1

The correct option is B 34.04%

Mass of Bromine = 80u

Mass of $AgBr$ = 188u

Weight of $AgBr$ = 0.12g

Weight of organic compound = 0.15g

$\text{Percentage of Bromine}=\frac{\text{Molar Mass of Bromine}}{\text{Molar Mass of}AgBr}\times \frac{\text{Weight of}AgBr}{\text{Weight of organic compound}}\times 100$

$\text{Percentage of Bromine}=\frac{80}{188}\times \frac{0.12}{0.15}\times 100=34.04\%$

Hence, option $B$ is correct answer.