Question

In case of the circuit arrangement shown below, the equivalent resistance between $A$ and $B$ is:

• A. $10\Omega$
• B. $2.5\Omega$
• C. $\frac{50}{3}\Omega$
• D. None of the above

Answer 1

The correct option is C $\frac{50}{3}\Omega$

Given: A circuit arrangement with resistors each of $10\Omega$ resistance

To find the equivalent resistance between A and B

Solution:

There is no current flowing through arm DE (refer the above figure). So resistors of arm FD and DC are in series, i.e., $20\Omega$.

Now resistor $20\Omega$ and resistor of arm FC i.e., $10\Omega$ are in parallel. So the combined resistance will be $\frac{20\times 10}{20+10}=\frac{200}{30}=\frac{20}{3}\Omega$

This is in series with the resistor, i.e., $10\Omega$ of the arm CE.

So the equivalent resistance between A and B will be $\frac{20}{3}+10=\frac{50}{3}\Omega$