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Question

In Δ ABC, A=50, BC=8 cm. Find the circumdiameter of the triangle [sin 50=0.77]


A

9.8 cm

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B

12.54 cm

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C

10.38 cm

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D

11.4 cm

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Solution

The correct option is C

10.38 cm


Draw diameter BD and connect DC

In Δ BCD, D=50, (Angle subtended by the same chord BC)

C=90 (Angle subtended by diameter BD on circumference)

In Δ BCD

sin 50=BCBD=8BD

BD=8sin 50=80.77=10.38 cm


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