Question

$In\Delta ABC,\angle B={35}^{\circ },\angle C={65}^{\circ }\text{and the bisector of}\angle BAC\text{meets BC in X. Arrange AX, BX and CX in descending order.}$

Answer 1

Given: In Δ ABC, ∠ B = 35°, ∠ C = 65° and the bisector of ∠ BAC meets BC in X.
In ∆ABX,∵ ∠BAX>∠ABX∴ BX>AX
...i
Similarly, in ∆ACX,∵ ∠ACX>∠XAC∴ AX>CX
...ii
From i and ii, we getBX>AX>CX