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Question

In ΔABCΔPQR, M is the midpoint of BC and N is the midpoint of QR. The area of ΔABC= 100 sq. cm and the area of ΔPQR= 144 sq. cm. If AM=4 cm, then PN is:

A
4.8 cm
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B
12 cm
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C
4 cm
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D
5.6 cm
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Solution

The correct option is A 4.8 cm
ar(ABC)ar(PQR)=100144
If triangles are similar then ratio of their areas is equal to ratio of square of their corresponding sides
AB2PQ2=100144ABPQ=1012
AM and PN are medians
Therefore, AMPN=ABPQ
4PN=1012PM=4.8cm

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