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Question

In ΔPQR, right-angled at Q,PR+QR=25cm and PQ=5cm. Determine the values of sinP,cosP and tanP.

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Solution

Let PR=x

QR=25x

(PQ)2+(QR)2=(PR)2

52+(25x)2=x2

25+(25)250x+x2=x2

50x=(25)2+25

50x=650

x=13

PR=13 QR=2513=12

cosP=PQPR=513

sinP=QRPR=1213

tanP=QRPR=125

1361623_1185761_ans_e68a244a1dd64bffaa6b17e3a0f3e890.png

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