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Question

In dilute alkaline solution, $$MnO^-_4$$ changes to:


A
MnO24
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B
MnO2
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C
Mn2O3
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D
MnO
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Solution

The correct option is D $$MnO^{2-}_4$$
In the dilute alkaline solution, $$MnO^-_4$$ changes to $$MnO^{2-}_4$$.
In this reaction, Mn(VII) accepts an electron to form Mn(VI).
$$MnO^-_4 \rightarrow MnO^{2-}_4 +e^-$$

So, the correct option is (A)

Chemistry

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