Question

In $\Delta ABC,\angle B={55}^o$ and $\angle A={45}^o$. Arranging the sides in descending order we get:

• A. $AB>BC>AC$
• B. $BC>AB>AC$
• C. $AC>AB>BC$
• D. $AB>AC>BC$

Answer 1

The correct option is D $AB>AC>BC$

In $\Delta ABC,\angle B={55}^o$ and $\angle A={45}^o$
$\therefore \angle C={80}^o(\because \angle A+\angle B+\angle C={180}^o)$
$\therefore$ Arranging the angles in descending order, we get
$\angle C,\angle B$ and $\angle A$

Since, the angles and the opposite sides of a triangle have same relation

Therefore, arranging the sides in descending order we get, $AB,AC$ and $BC.$