Question

In $\Delta PQR,\angle P={67}^o$ and $\angle Q={76}^o$. Arrange the sides in descending order according to the lengths we get,

• A. $PR>QR>PQ$
• B. $PQ>QR>PR$
• C. $PQ>QR>PR$
• D. $QR>PQ>PR$

Answer 1

The correct option is A $PR>QR>PQ$

In $\Delta PQR,\angle P={67}^o$ and $\angle Q={76}^o$
$\therefore \angle R={37}^o$
$(\because \angle P+\angle Q+\angle R={180}^o).$

Now arranging the angles in descending order, we get
$\angle Q>\angle P>\angle R$ .

Sides opposite to greater angle are greater in length and the angles and the opposite sides of a triangle have same relation.

Therefore, the sides arranged in descending order, we get $PR>QR>PQ.$