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Question

In double-slit experiment, the slits are separated by a distance $$d$$ and the screen is at a distance $$D$$ from the slits. If a maximum is formed just opposite to each slit, then what is the order of the fringe so formed?


A
d22λD
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B
2d2λD
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C
d2λD
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D
d24λD
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Solution

The correct option is A $$\cfrac { { d }^{ 2 } }{ 2\lambda D } $$
Constructive interference has occurred in front of one slit, its distance from centre is $$ x=\dfrac { d }{ 2 } $$
For bright fringes, $$ x=\dfrac { n\lambda D }{ d } =\dfrac { d }{ 2 } \Rightarrow n=\dfrac { { d }^{ 2 } }{ 2\lambda D }   $$

Physics

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