Question

# In double-slit experiment, the slits are separated by a distance $$d$$ and the screen is at a distance $$D$$ from the slits. If a maximum is formed just opposite to each slit, then what is the order of the fringe so formed?

A
d22λD
B
2d2λD
C
d2λD
D
d24λD

Solution

## The correct option is A $$\cfrac { { d }^{ 2 } }{ 2\lambda D }$$Constructive interference has occurred in front of one slit, its distance from centre is $$x=\dfrac { d }{ 2 }$$For bright fringes, $$x=\dfrac { n\lambda D }{ d } =\dfrac { d }{ 2 } \Rightarrow n=\dfrac { { d }^{ 2 } }{ 2\lambda D }$$Physics

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