In Fig 2, a circle touches the side DF of $^{Δ} E D F$ at H and touches ED and EF produced at K and M respectively. If EK = 9 cm, then the perimeter of $^{Δ} E D F$ (in cm) is:

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Solution

The correct option is A 18
EK = 9 cm
As length of tangents drawn from an external point to the circle are equal.
EK = EM = 9 cm
Also, DH = DK and FH = FM ......(1)
EK = EM = 9 cm
ED + DK = 9 cm and EF + FM = 9 cm
ED + DH = 9 cm and EF + FM = 9 cm [From equation (i)] ....(ii)
= ED + DH + HF + EF
= (9 + 9) cm [From equation (ii)]
= 18 cm

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In Fig 2, a circle touches the side DF of ΔEDF at H and touches ED and EF produced at K and M respectively. If EK = 9 cm, then the perimeter of ΔEDF (in cm) is:

In Fig 2, a circle touches the side DF of $^{Δ} E D F$ at H and touches ED and EF produced at K and M respectively. If EK = 9 cm, then the perimeter of $^{Δ} E D F$ (in cm) is: