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Question

In fig., the area of triangle ABC (in sq. units) is:
494254_960ebb8d35e7478f9ae68c4a1770db0a.png

A
15
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B
10
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C
7.5
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D
2.5
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Solution

The correct option is B 7.5
Given: Coordinates of Point A(1,3),B(1,0) and C(4,0)
Construction: Drop a perpendicular from A on x axis, which meets x-axis at D(1,0)
Now in ΔADC,AD=3,DC=3
Area of ΔADC=12×DC×AD
=12×3×3=92 cm2

Now in ΔADB,AD=3,DB=2
Area of ΔADB=12×DB×AD
=12×2×3=3 cm2

Area of ΔABC= Ara of ΔADC+ Area of ΔABD
=92+3=152=7.5 cm2

577432_494254_ans_9f085d57d4514b4989555b16e971f304.png

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