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Question

In figure, AOBCA represents a quadrant of a circle of radius 3.5cm with centre O. Calculate the area of the shaded portion (Take π=227)

320311_5a7c7de825d24195b54659b06a222523.png

A
2.156cm2
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B
4.653cm2
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C
6.125cm2
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D
None of these
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Solution

The correct option is C 6.125cm2
We are given that radius of the quadrant =3.5cm

Area of the quadrant AOBCA
=14πr2

=14×227×(3.5)2

=9.625cm2

Area of the triangle AOD
=12×base×height

=12×OA×OD

=12×3.5×2cm2

=3.5cm2

Hence Area of the shaded region =Area of the quadrant-Area of the triangle AOD

=9.6253.5

=6.125cm2

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