Question

# In Figure , common tangents AB and CD to the two circles with centres $$O_1$$ and $$O_2$$ intersect at E. Prove that AB = CD.

Solution

## From the given figure, $$AB$$ and $$CD$$ are common tangents on both the circles. $$AB$$ and $$CD$$ intersect at $$E$$.Now, $$EA = EC$$ (Tangents drawn on circle from same point)$$EB = ED$$ (Tangents drawn on circle from same point)$$EA + EB = EC + ED$$$$AB = CD$$MathematicsRS AgarwalStandard X

Suggest Corrections

0

Similar questions
View More

Same exercise questions
View More

People also searched for
View More