In figure D and E are the mid points of sides AB and AC respectively of $△ A B C$ . Find $∠ E D B$

110^{\circ}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

120^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

70^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

80^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $110^{\circ}$
From the fig,
$∠ D A E = 60^{\circ}$
$∠ D E A = ∠ A C B = 50^{\circ}$ [Co-interior angle]
From $△ A D E$ by angle sum ppty
$∠ A D E + ∠ D E A + ∠ D A E = 180 °$
$\Rightarrow ∠ A D E = 180^{\circ} - 60^{\circ} - 50^{\circ} = 70^{\circ}$
$∠ E D B = 180^{\circ} - ∠ A D E = 180^{\circ} - 70^{\circ} = 110^{\circ}$ ..... [Straight angle]

Suggest Corrections

Similar questions

Q. In the figure

D

and

E

are the mid-points of sides

A B

and

A C

respectively of

Δ A B C

. Find

∠ E D B .

In the figure, $△ A B C$ is an isosceles triangle in which AB = AC. If D and E are the mid-points of sides AB and AC respectively and $∠ D O E = 120^{\circ}$ , then find $∠ O D E$ .

In the figure, ABC is an isosceles triangle in which AB = AC. If D and E are the mid-points of sides AB and BC respectively and $∠$ DOE = 120º, find
$∠$ ODE.

In the figure, ABC is an isosceles triangle in which AB=AC. If D and E are the mid-points of sides AB and BC respectively and $∠$ DOE = 120º, find
$∠$ ODE.

Q. In

Δ A B C

, D, E and F are mid-points of sides AB, BC and AC respectively.

Join BYJU'S Learning Program

In figure D and E are the mid points of sides AB and AC respectively of △ABC. Find ∠EDB

The correct option is A 110∘From the fig,∠DAE=60∘∠DEA=∠ACB=50∘ [Co-interior angle]From △ADE by angle sum ppty∠ADE+∠DEA+∠DAE=180°⇒∠ADE=180∘−60∘−50∘=70∘∠EDB=180∘−∠ADE=180∘−70∘=110∘ ..... [Straight angle]

In figure D and E are the mid points of sides AB and AC respectively of $△ A B C$ . Find $∠ E D B$