In figure $H E L P$ is parallelogram. if $O E = 4 c m$ and $H L$ , is $5 c m$ more then $P E$ Find $O H$ .

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Solution

we know that the diagonals of the parallelogram bisect each other.
$O E = 4$
$H L = 5 + P E$
$P E = 2 O E, H L = 2 O H$
$2 O H = 5 + 2 O E = 5 + 8 = 13$
$O H = 6.5 c m$

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In figure HELP is parallelogram. if OE=4 cm and HL, is 5 cm more then PE Find OH.

we know that the diagonals of the parallelogram bisect each other.OE=4HL=5+PEPE=2OE,HL=2OH2OH=5+2OE=5+8=13OH=6.5 cm

In figure $H E L P$ is parallelogram. if $O E = 4 c m$ and $H L$ , is $5 c m$ more then $P E$ Find $O H$ .

we know that the diagonals of the parallelogram bisect each other.
$O E = 4$
$H L = 5 + P E$
$P E = 2 O E, H L = 2 O H$
$2 O H = 5 + 2 O E = 5 + 8 = 13$
$O H = 6.5 c m$