Question

# In figure, line $$l ||m$$, $$\angle 1=120^o$$ and $$\angle 2=100^o$$, find out $$\angle 3$$ and $$\angle 4$$.

Solution

## As per the given figure, $$\angle 2 = \angle y = 100^o$$           [corresponding angles ]$$\angle 3 = 180^o - \angle y =180- 100^o = 80^o$$    [ Angles in a straight line ]$$\angle x = 180^o - \angle 1 =180- 120^o = 60^o$$    [ Angles in a straight line ]We know that sum of angles in a triangles is $$180^o$$$$\angle x + \angle 3 + \angle 4 =180^o$$    $$60 + 80 + \angle 4 =180^o$$$$\angle 4 =180-140^o$$$$\therefore \angle 3 = 80^o$$ and    $$\angle 4 =40^o$$Mathematics

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