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Question

In figure, line $$l ||m$$, $$\angle 1=120^o$$ and $$\angle 2=100^o$$, find out $$\angle 3$$ and $$\angle 4$$.
1677545_112ddb836afd45408903ced895c1b9fc.png


Solution

As per the given figure,
 $$ \angle 2 = \angle y = 100^o$$           [corresponding angles ]

$$ \angle 3 = 180^o - \angle y =180- 100^o = 80^o $$    [ Angles in a straight line ]

$$ \angle x = 180^o - \angle 1 =180- 120^o = 60^o $$    [ Angles in a straight line ]

We know that sum of angles in a triangles is $$180^o$$

$$ \angle x + \angle 3 + \angle 4 =180^o$$    

$$ 60 + 80 + \angle 4 =180^o$$

$$  \angle 4 =180-140^o$$

$$ \therefore \angle 3 = 80^o $$ and
    $$ \angle 4 =40^o$$

1468437_1677545_ans_93c61065ab944ebfa933fb25a30eaaa0.png

Mathematics

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