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Question

In figure, the angle of inclination of the incline plane is 30°. The horizontal velocity
V0 so that the particle hits the incline plane perpendicularly is xghy. Then value of x × y is  (Where, x & y are integer and coprime.)


Solution

In a direction along the inclined plane, 
0=V0cos30°gsin30°t  t =3V0g 
In a direction perpendicular to incline, 
Hcos30°=V0sin30°t(gcos30°)t22
. Putting the value of t and solving, we get V0=2gH5

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