In fructose, the possible optical isomers are

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 8
Fructose has three chiral centres and hence $2^{3}$ = 8 optical isomers are possible.

Suggest Corrections

Similar questions

The maximum number of possible optical isomers in 1-bromo-2-methyl cyclobutane?

[C o (e n)_{2} C l_{2}]^{+}

C H_{2} O H C H O H C H O H C H O

Join BYJU'S Learning Program