Question

In given figure, if AB || CD || EF, PQ || RS, $\angle RQD={25}^o$ and $\angle CQP={60}^o$, then $\angle QRS$ is equal to .............

• A. 85${}^o$
• B. 135${}^o$
• C. 145${}^o$
• D. 110${}^o$

Answer 1

The correct option is C 145${}^o$

Given figure, if AB || CD || EF, PQ || RS, RQD=25o and CQP=60o,
Then $\angle SRB=\angle CQP={60}^0$
OR $\angle QRA=\angle RQD={25}^0$
So $\angle ARS+\angle SRB={180}^0$
$\therefore \angle ARS=120-60={120}^0$
$\angle QRS=\angle ARS+\angle QRA=120+25={145}^0$