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Question

In Haber's process, the equivalent weight of nitrogen gas is:
  1. 3 M
  2. M6
  3. M
  4. M3


Solution

The correct option is B M6
N2+3H22NH3
Here, the oxidation state of N changes from 0 to -3 when nitrogen gas becomes ammonia. Since there are two nitrogen atoms in the nitrogen gas molecule, the total change in oxidation number is 6. , the equivalent weight = M6

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