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Question

In how many ways, a party of 5 men and 5 women be seated at a circular table, so that no two women are adjacent?


  1. 720

  2. 14400

  3. 1440

  4. 2880


Solution

The correct option is D

2880


The 4 men can be seated at a circular table such that there is a vacant seat between every pair of men in (5 – 1)! = 4! = 24 ways. Now, 5 vacant seats can be occupied by 5 women in 5! = 120 ways.

Hence, the required number of seating arrangements = 24 x 120 = 2880

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