in how many ways can 1000 be represented as a sum of consecutive odd integers

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Solution

Hi,
One possible way is ;

 (n-2) + (n-1) + n + (n+1) + (n+2) = 1000
 
                                 5n = 1000

                                  n = 200
so answer is 198,199,200,201,202
and I guess it is only possible way.
Regards

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in how many ways can 1000 be represented as a sum of consecutive odd integers

Hi, One possible way is ; (n-2) + (n-1) + n + (n+1) + (n+2) = 1000 5n = 1000 n = 200 so answer is 198,199,200,201,202 and I guess it is only possible way. Regards

Hi,
One possible way is ;
(n-2) + (n-1) + n + (n+1) + (n+2) = 1000 5n = 1000 n = 200 so answer is 198,199,200,201,202 and I guess it is only possible way. Regards