CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In how many ways can a mixed double game can be arranged from amongst 8 couples if no husband and wife play in the same game

Open in App
Solution

8C2
2 men are selected from 8 men 8C2 ways


Since no husband and wife should be in same game,
two women out of remaining 6 are chosen in 6C2 ways
Now one team can be chosen as (M1,W1)or(M1,W2)(M1,W1)or(M1,W2) in 2 ways.
The required no. of arrangements = 8C2*6C2*2
8C2×6C2×2
=840

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Why Do We Need to Manage Our Resources?
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon