Question

# In how many ways can the letters of the word $$PERMUTATIONS$$ be arranged, if the words start with $$P$$ and end with $$S$$?

A
1814400
B
1814405
C
1824050
D
None of these

Solution

## The correct option is A $$1814400$$Let first position be $$P$$ and last position be $$S$$(both are fixed)Since letter are repeatingHence we use this formula $$\dfrac{n!}{{p}_{1}!{p}_{2}!{p}_{3}!}$$Total number of letters$$=n=10$$and since, $$2T$$$$\Rightarrow {p}_{1}=2$$Total arrangements$$=\dfrac{10!}{2!}=181440$$Maths

Suggest Corrections

0

Similar questions
View More

People also searched for
View More