In how much time (in seconds) should a charge of $10 C$ flow between the two terminals so as to maintain a constant current of $100 A$ ?

1/10 s

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10 s

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110 s

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1/110 s

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Solution

The correct option is A
1/10 s

Current is the rate of flow of charge.

i.e., I = $\frac{Q}{t}$

where $Q$ = charge flowing, $t$ = time

So time, t = $\frac{Q}{I}$ = $\frac{10}{100}$ = $\frac{1}{10}$ s

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In how much time (in seconds) should a charge of 10 C flow between the two terminals so as to maintain a constant current of 100 A?

The correct option is A 1/10 s Current is the rate of flow of charge. i.e., I = Qt where Q = charge flowing, t = time So time, t = QI = 10100 = 110 s

In how much time (in seconds) should a charge of $10 C$ flow between the two terminals so as to maintain a constant current of $100 A$ ?

The correct option is A
1/10 s

Current is the rate of flow of charge.

i.e., I = $\frac{Q}{t}$

where $Q$ = charge flowing, $t$ = time

So time, t = $\frac{Q}{I}$ = $\frac{10}{100}$ = $\frac{1}{10}$ s