CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

In Newton's experiment of cooling, the water equivalent of two similar calorimeters is 10 gm each. They are filled with 350 gm of water and 300 gm of a liquid (equal volumes) separately. The time taken by water and liquid to cool from 70C to 60C is 3 min and 95 sec respectively. The specific heat of the liquid will be


  1. 0.3 Cal/gm ´°C

  2. 0.5 Cal/gm ´°C

  3. 0.6 Cal/gm ´°C

  4. 0.8 Cal/gm ´°C


Solution

The correct option is C

0.6 Cal/gm ´°C


Sl=1ml[tltw(MwCw+W)W] 

= 1300[953×60(350×1+10)10]=0.6Cal/gm×C 

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image