You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Production

Velocity Triangle in Orthogonal Machining

In orthogonal...

Question

In orthogonal cutting operation, the ratio of the chip thickness to the depth of cut is 1.5. If the cutting speed is 10 m/s, then the chip flow velocity will be

6.67 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 6.67 m/s
Using conservation of mass,
$V t_{0} = V_{c} t_{c}$

$∴$ $V_{c} = \frac{V t_{0}}{t_{c}} = 10 \times \frac{1}{1.5} = 6.67 m / s$

Suggest Corrections

Similar questions

Common Data:
An orthogonal operation is carried out at $20 m / m i n$ cutting speed, using a cutting tool of rake angle $15$ degree. The chip thickness is $0.4 m m$ and uncut chip thickness is $0.2 m m$

The chip velocity (in $m / m i n$ ) is

Q. In an orthogonal cutting test, the following observation were made
Cutting force

= 1200 N

Thrust force

= 500 N

Tool rake angle

= z e r o

Cutting speed

= 1 m / s

Depth of cut

= 0.8 m m

Chip thickness

= 1.5 m m

Chip speed along the tool rake face will be

Q. Common Data:
An orthogonal operation is carried out at

20 m / m i n

cutting speed, using a cutting tool of rake angle

15

degree. The chip thickness is

0.4 m m

and uncut chip thickness is

0.2 m m

The shear angle (in degrees) is

Q. In an orthogonal cutting test, the following observation were made
Cutting force

= 1200 N

Thrust force

= 500 N

Tool rake angle

= z e r o

Cutting speed

= 1 m / s

Depth of cut

= 0.8 m m

Chip thickness

= 1.5 m m

Friction angle during machining will be

Q. In an orthogonal cutting test with a tool of rake angle 15 deg, the following observations were made: chip thickness ratio = 0.37, horizontal cutting force = 1000 N, vertical cutting force = 1500 N.

The machining constant for the given machining operation is

Join BYJU'S Learning Program

In orthogonal cutting operation, the ratio of the chip thickness to the depth of cut is 1.5. If the cutting speed is 10 m/s, then the chip flow velocity will be

The correct option is A 6.67 m/sUsing conservation of mass, Vt0=Vctc ∴ Vc=Vt0tc=10×11.5=6.67m/s

The correct option is A 6.67 m/s
Using conservation of mass,
$V t_{0} = V_{c} t_{c}$

$∴$ $V_{c} = \frac{V t_{0}}{t_{c}} = 10 \times \frac{1}{1.5} = 6.67 m / s$