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Velocity Triangle in Orthogonal Machining

In orthogonal...

Question

In orthogonal cutting operation, the ratio of the chip thickness to the depth of cut is 1.5. If the cutting speed is 10 m/s, then the chip flow velocity will be

6.67 m/s

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10 m/s

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15 m/s

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20 m/s

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Solution

The correct option is A 6.67 m/s
Using conservation of mass,
$V t_{0} = V_{c} t_{c}$

$∴$ $V_{c} = \frac{V t_{0}}{t_{c}} = 10 \times \frac{1}{1.5} = 6.67 m / s$

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In orthogonal cutting operation, the ratio of the chip thickness to the depth of cut is 1.5. If the cutting speed is 10 m/s, then the chip flow velocity will be

The correct option is A 6.67 m/sUsing conservation of mass, Vt0=Vctc ∴ Vc=Vt0tc=10×11.5=6.67m/s

The correct option is A 6.67 m/s
Using conservation of mass,
$V t_{0} = V_{c} t_{c}$

$∴$ $V_{c} = \frac{V t_{0}}{t_{c}} = 10 \times \frac{1}{1.5} = 6.67 m / s$