You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Production

Specific Energy in Machining

In orthogonal...

Question

In orthogonal turning of medium carbon steel, the specific machining energy is $2. J / m m^{3}$ . The cutting velocity, feed and depth of cut are $120 m / m i n, 0.2 m m / r e v$ and $2 m m$ respectively. The main cutting force in $N$ is

40

No worries! We‘ve got your back. Try BYJU‘S free classes today!

80

No worries! We‘ve got your back. Try BYJU‘S free classes today!

400

No worries! We‘ve got your back. Try BYJU‘S free classes today!

800

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $800$
The energy consumption per unit volume of material removal, commonly known as specific energy,
Cutting force $= 2 \times 1000 \times 0.2 \times 2 = 800 N$

Suggest Corrections

Similar questions

Q. The main cutting force acting on a tool during the turning (orthogonal cutting) operation of metal is

400 N

. The turning was performed using

2 m m

depth of cut and

0.1 m m / r e v

feed rate. The specific cutting pressure (in

N / m m^{2}

) is

Linked Question
A low carbon steel bar of $147 m m$ diameter with a length of $630 m m$ is being turned with an uncoated carbide insert. The observed tool lives are $24 m i n$ and $12 m i n$ for cutting velocities of $90 m / m i n$ and $120 m / m i n$ respectively. The feed and depth of cut are $0.2 m m / r e v$ and $2 m m$ respectively. Use the unmachined diameter to calculate the cutting velocity.

When tool life is $20 m i n$ the cutting velocity in $m / m i n$ is

Linked Question
A low carbon steel bar of $147 m m$ diameter with a length of $630 m m$ is being turned with an uncoated carbide insert. The observed tool lives are $24 m i n$ and $12 m i n$ for cutting velocities of $90 m / m i n$ and $120 m / m i n$ respectively. The feed and depth of cut are $0.2 m m / r e v$ and $2 m m$ respectively. Use the unmachined diameter to calculate the cutting velocity.

Neglect over-travel or approach of the tool. When too life is $20 m i n$ , the machining time in min for a single pass is

Q. In orthogonal turning of a low carbon steel bar of diameter

150 m m

uncoated carbide tool the cutting velocity is

90 m / m i n

. The feed is

0.24 m m / r e v

and the depth of cut is

2 m m

. The chip thickness obtained is

0.48 m m

. If the orthogonal rake angle is zero and the principal cutting edge angle is

90^{o}

, the shear angle in degree is

Common Data:
A disc of $200 m m$ outer and $80 m m$ inner diameter is faced at a feed of $0.1 m m / r e v$ with a depth of cut of $1 m m$ . The facing operation is undertaken at a constant cutting speed of $90 m / m i n$ in a CNC lathe The main (tangential) cutting force is $200 N$

Neglecting the contribution of the feed force towards cutting power, the specific cutting energy in $J / m m^{3}$ is

Join BYJU'S Learning Program

In orthogonal turning of medium carbon steel, the specific machining energy is 2.J/mm3. The cutting velocity, feed and depth of cut are 120m/min,0.2mm/rev and 2mm respectively. The main cutting force in N is

The correct option is D 800The energy consumption per unit volume of material removal, commonly known as specific energy, Cutting force =2×1000×0.2×2=800N

In orthogonal turning of medium carbon steel, the specific machining energy is $2. J / m m^{3}$ . The cutting velocity, feed and depth of cut are $120 m / m i n, 0.2 m m / r e v$ and $2 m m$ respectively. The main cutting force in $N$ is

The correct option is D $800$
The energy consumption per unit volume of material removal, commonly known as specific energy,
Cutting force $= 2 \times 1000 \times 0.2 \times 2 = 800 N$