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Question

In photosynthesis, 6 molecules of carbon dioxide combine with an equal number of water molecules through a complex series of reactions to give a molecule of glucose having a molecular formula C6H12O6. How many grams of water would be required to produce 18 g of glucose? Compute the volume of water so consumed assuming the density of water to be 1 g cm3.
Rreaction that takes place during photosynthesis is:
6CO2+6H2O C6H12O6+6O2

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Solution


Molecular mass of 6H2O = 6[(1 x 2) + 16)] =6 x 18 =108g
Molecular mass of C6H12O6 = 12 x 6 + 1 x 12 +16 x 6 = 180g

180 g of glucose needs (6×18)g of water
Therefore, 18 g of glucose will need 108180×18 g of water = 10.8 g

Given, density of water to be 1 g cm3
mass of water = 10.8 g
Therefore, Volume of water used =MassDensity=10.8g1g cm3=10.8cm3

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