In PQR, PQ = PR and R = 65°, then P =?
50°
120°
40°
75°
Since the angles opposite equal sides of a triangle are equal.
So ∠R = ∠Q= 65o
Also, sum of angles of a triangle is 180°.
65o + 65o + ∠P = 180o
∠P = 50°
In a ΔPQR, PQ = PR and ∠R = 65°, then ∠P =?