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Question

In Pythagoras exercise we have questions which says DB=3CD, or something like that is given to us in the question. And with this we find out the measurements of the sides,  how to find those lengths.


Solution

let CD = x

DB = 3CD = 3x

According to Pythagoras theorem in the triangle BDC

DB should be hypotaneous and CD should be base or lenght

therefore BC = √(DB^2 - CD^2)

BC = √(9x^2 - x^2)  = √8x^2  = 2√2x

Hence side BC = 2√2CD,    hypotaneous DB = 3CD






 

Mathematics

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