In reaction sequence, molecule M and reagent R respectively are:

C H_{3} C H_{2}

and

N a O H

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C H_{3} C H_{2} O H

and

H_{2} S O_{4}

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C H_{2} C l - C H_{2} O H

and

a q . N a H C O_{3}

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C H_{3} - C H_{3}

and heat

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Solution

The correct option is D $C H_{2} C l - C H_{2} O H$ and $a q . N a H C O_{3}$
A molecule of hypochlorous acid ( $H O C l$ ) adds to $C = C$ double bond of ethylene to form $C H_{2} C l - C H_{2} O H$ (molecule $M$ ). Hydrolysis with aq $N a H C O_{3}$ (reagent $R$ ) forms ethylene glycol.
$H_{2} C = C H_{2} ethylene H O C l - -- \to C H_{2} C l - C H_{2} O H molecule M a q . N a H C O_{3} - ------ \to C H_{2} O H - C H_{2} O H ethylene glycol$

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Similar questions

C H_{2} C H_{3} | C | O H - C H_{3} | C H C H_{3} I I \leftarrow - C H_{3} C H_{3} | C | C H_{3} C H = C H_{2} I \to C H_{3} - C H_{3} | C | C H_{3} - C | O H H C H_{3}

R - C H_{2} O H \to R - C H_{3}

C H_{3} C H_{2} - O H

C H_{3} - O - C H_{3}

C H_{3} C H_{2} - O H

C H_{3} - O - C H_{3}

In the reaction $C H_{3} - C H_{3} | C H - C H_{2} O - C H_{2} - C H_{3} + h e a t e d H I \to . . . . . . . . . .$

Which of the following compounds will be formed?

Which of the following compounds gives fastest reaction with HBr and why

(i) (CH3)3 COH

(ii) CH3 CH2 CH2OH

(iii) CH3 CHOH CH3

(iv) CH3 (CH3) CH CH2OH

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