Question

In rectangle ABCD, DE and BF are 2 cm and 5 cm respectively. If AB and BC are 12 cm and 10 cm respectively, then find area of shaded region

A
10 cm2
B
30 cm2
C
80 cm2
D
120cm2

Solution

The correct option is B 80 cm2Given : ABCD is a rectangle  AB = 12 cm, BC = 10 cm DE = 2 cm, BF = 5 cm Area of rectangle = length×breadth Area of rectangle ABCD = AB×BC                                         = 12×10 = 120 cm2   Area of triangle = 12×base×height Area of △ABF = 12×AB×BF =  12×12×5 = 6×5 = 30 cm2 Area of △ADE = 12×DE×AD =  12×10×2 = 5×2 = 10 cm2 Area of shaded region = area of rectangle ABCD - Area of △ABF - Area of △ADE = 120 - 30 - 10 = 80 cm2

Suggest corrections