In Rutile $(T i O_{2})$ structure, if the number of effective number of molecules in each unit cell is $x$ and the coordination number of oxygen in each unit cell is $y$ , then what is the value of $x + y$ ?
In the figure given, redballs represent oxygen atoms and blue balls represents titanium atoms.

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Solution

Titanium atoms form bcc arrangement. A bcc unit cell contains $2$ atoms per unit cell. Hence, $x = 2$
Oxygen atoms are present in trigonal voids. The coordination number in trigonal void is $3$ . Hence, $y = 3$
Thus, $x + y = 2 + 3 = 5$

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In Rutile (TiO2) structure, if the number of effective number of molecules in each unit cell is x and the coordination number of oxygen in each unit cell is y, then what is the value of x+y? In the figure given, redballs represent oxygen atoms and blue balls represents titanium atoms.

Titanium atoms form bcc arrangement. A bcc unit cell contains 2 atoms per unit cell. Hence, x=2Oxygen atoms are present in trigonal voids. The coordination number in trigonal void is 3. Hence, y=3Thus, x+y=2+3=5

Titanium atoms form bcc arrangement. A bcc unit cell contains $2$ atoms per unit cell. Hence, $x = 2$
Oxygen atoms are present in trigonal voids. The coordination number in trigonal void is $3$ . Hence, $y = 3$
Thus, $x + y = 2 + 3 = 5$