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Inter Conversion between Standard and Normal Forms

In standard f...

Question

Question 11

In standard form, the number 72105.4 is written as $7.21054 \times 10^{n},$ where $n$ is equal to
(a) 2
(b) 3
(c) 4
(d) 5

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Solution

We know that, if the given number is greater than or equal to 10, then the power of 10 (i.e. $n$ ) is a positive integer equal to the number of places the decimal point has been shifted.
Hence, $72105.4 = 7.21054 \times 10^{4}$

Thus, n = 4 .

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In standard form, the number 829030000 is written as $K \times 10^{8},$ where $K$ is equal to:
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\frac{1}{l o g_{3} π} + \frac{1}{l o g_{4} π} > x

, then x is equal to

l o g_{3} 2, l o g_{3} (2^{x} - 5) a n d l o g_{3} (2^{x} - \frac{7}{2})

are in AP, then x is equal to

l o g_{3} 2, l o g_{3} (2^{x} - 5)

l o g_{3} (2^{x} - \frac{7}{2})

are in A.P. then

x

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Inter Conversion between Standard and Normal Forms

Standard VII Mathematics

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