In the above figure, if RB, SC and TO are perpendiculars to BD with the length indicated, then xy is equal to
A
pq
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B
pp+q
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C
qp
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D
qp+q
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Solution
The correct option is Apq In triangles RBD and SCD ∠D is common to both. and ∠B=∠C (because each angle is right angle) ∵ Triangles RBD and SCD are equiangular ∴RBSC=BDCD or, xz=p+qq Similarly triangles TDB and SCB are equiangular ∴SCTD=BCBD or, zy=qp+q ∴xz×zy=p+qq×pp+q ∴xy=pq