Question

# In the above reaction if $$A$$ is $$NH_4Cl$$ and $$D$$ is $$CO_2$$ then $$B$$ & $$C$$ respectively are :(A) $$+ NaOH \rightarrow NaCl +NH_3+H_2O$$$$NH_3+CO_2+H_2O\rightarrow (B)$$(B) $$+NaCl\rightarrow (C) + NH_4Cl$$(C) $$\rightarrow Na_2CO_3+H_2O+(D)$$

A
NH4HCO3,NaHCO3
B
NaHCO3,NH4HCO3
C
(NH4)2CO3,Na2CO3
D
Na2CO3,(NH4)2CO3

Solution

## The correct option is A $$NH_{4}HCO_{3},NaHCO_{3}$$Ammonium chloride reacts with sodium hydroxide to form sodium chloride, ammonia and water.$$NH_{ 4 }Cl+NaOH\xrightarrow { Heat } NaCl+NH_{ 3 }+H_{ 2 }O\\ \quad (A)$$Ammonia reacts with carbon dioxide and water to form ammonium bicarbonate.$$NH_{ 3 }+CO_{ 2 }+H_{ 2 }O\xrightarrow { } NH_{ 4 }HCO_{ 3 }\\ \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad (B)$$Ammonium carbonate reacts with sodium chloride to form sodium bicarbonate and ammonium chloride.$$NH_{ 4 }HCO_{ 3 }+NaCl\xrightarrow { } NaHCO_{ 3 }+NH_{ 4 }Cl\\ \quad \quad (B)\quad \quad \quad \quad \quad \quad \quad \quad (C)$$Sodium bicarbonate decomposes to give sodium carbonate, water and carbon dioxide.$$2NaHCO_{ 3 }\xrightarrow { } Na_{ 2 }CO_{ 3 }+H_{ 2 }O+CO_{ 2 }\\ \quad \quad (C)\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad (D)$$Chemistry

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