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Question

In the above reaction the attack of a nucleophile would be from which side:

3CH32C|HCH31CH2Claq.KOH−−−−CH3CH|CH3CH2OH

A
On the front side of Cl and C1 carbon
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B
On C2
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C
On the rear side of Cl and C1 carbon
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D
On C3 carbon
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Solution

The correct option is C On the rear side of Cl and C1 carbon
This is a SN2 reaction. Since, steric hindrance is not there, so, as soon as Cl leaves the C1 carbon from the front side, OH attacks the carbocation from the rear side of Cl and C1 carbon.

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