1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# In the arrangement shown in Fig.6.378, all pulleys are smooth and massless. When the system is released from the rest, acceleration of blocks 2 and 3 relative to 1 are 1msâˆ’2 downwards and 5msâˆ’2 downwards. respectively. Acceleration of block 3 relative to 4 is zero.Find the absolute acceleration ofblock 4.

A
2ms2 upwards
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
1ms2 downwards
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
3ms2 downwards
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.5ms2 upwards
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is C 3ms−2 downwardsacceleration of block 2 & 3 to 1 are 1 ms−1observer is standing on 1 \& looking downwards to a,4a3. So, a2+a1=1 m/s2−(I)a3+a1=5m/s2−(11)now, the obserwen is standing on 4 . therefore, a4−a3=0a4=a3−(III)now,consideningdinection4findinga1=a5+a44, a2+a32=a5[ for 2nd&3rd pully ]⇒2a1−a4=a2+a32⇒4a1=2a4+a3+a2[a4=a3]⇒4a1=3a3+a2⇒4a1=3(5−a1)+(1−a1)⇒8a1=16⇒a1=2m/s2now, a1+a2=1; a2=−1 m/s2⇒a3+a1=5Equation(11)⇒a3=5−2=3 m/s2↓⇒|a3=3m|s2Answer:- 3 m/s2downward(c).Thecorrectoptionisc

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Distance and Displacement
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program