You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Constrained Motion : Intuitive Approach

In the arrang...

Question

In the arrangement shown in figure, the relation between acceleration of blocks $m_{1}$ and $m_{2}$ is

a_{1} = 3 a_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 a_{1} = a_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a_{1} = 2 a_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 a_{1} = a_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $3 a_{1} = a_{2}$

Let $x$ be displacement of $m_{1}$ and $y$ be displacement of $m_{2}$
For constraint relation
$W_{n e t}^{T e n s i o n} = 0$
$- 3 T x + T y = 0$
$\Rightarrow y = 3 x$
Differentiating twice w.r.t. time,
$\Rightarrow a_{2} = 3 a_{1}$

Suggest Corrections

Similar questions

Q. Two blocks are arranged as shown in the figure. What will be the relation between the accelerations

a_{1}

of block

m_{1}

and

a_{2}

of block

m_{2}

, if the surface and the pulleys are frictionless and the strings are inextensible?

Q. Two blocks are arranged as shown in the figure. What will be the relation between the accelerations

a_{1}

of block

m_{1}

and

a_{2}

of block

m_{2}

, if the surface and the pulleys are frictionless and the strings are inextensible?

Q. In the arrangement shown in figure, the relation between acceleration of blocks

m_{1}

and

m_{2}

Q. In the arrangement shown in the figure the rod R is restricted to move in the vertical direction with acceleration

a_{1}

, and the block B can slide down the fixed wedge with acceleration

a_{2}

. The correct relation between

a_{1}

and

a_{2}

is given by :

Three blocks 1,2 and 3 are arranged with pulley and spring as shown in the figure. If string connecting blocks $m_{2}$ and $m_{3}$ is cut at point A, find the accelerations of masses $m_{1}$ , $m_{2}$ , and $m_{3}$ just after the string is cut at point A.

Join BYJU'S Learning Program

In the arrangement shown in figure, the relation between acceleration of blocks m1 and m2 is

The correct option is D 3a1=a2 Let x be displacement of m1 and y be displacement of m2 For constraint relation WTensionnet=0 −3Tx+Ty=0 ⇒y=3x Differentiating twice w.r.t. time, ⇒a2=3a1

In the arrangement shown in figure, the relation between acceleration of blocks $m_{1}$ and $m_{2}$ is

The correct option is D $3 a_{1} = a_{2}$

Let $x$ be displacement of $m_{1}$ and $y$ be displacement of $m_{2}$
For constraint relation
$W_{n e t}^{T e n s i o n} = 0$
$- 3 T x + T y = 0$
$\Rightarrow y = 3 x$
Differentiating twice w.r.t. time,
$\Rightarrow a_{2} = 3 a_{1}$