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Question

In the arrangement shown in the fig. The strings are light and inextensible. The surface over which blocks are placed is smooth. The acceleration and Tension in the string.
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A
53m/s2,203N
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B
56m/s2,103N
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C
56m/s2,53N
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D
65m/s2,103N
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Solution

The correct option is A $$\dfrac{5}{3}m/s^{2}, \dfrac{20}{3}N$$
$$ \begin{array}{l} \text { So Net force in Honizontal direction }=20 \cos 60^{\circ} \\ =10 \mathrm{~N} \\ \text { So accleration = Net force/Total mass } \\ \qquad \begin{aligned} \text { } \end{aligned} \\ =\left(\dfrac{10}{4+2}\right) \mathrm{m} / \mathrm{s}^{2} \\  =\dfrac{5}{3} \mathrm{~m} / \mathrm{s}^{2} \end{array} $$ 

$$ \text { and now FBD of } 2 \mathrm{~kg} \text { Block } $$ 

$$ \begin{array}{l} \text { So from } F B D \\ \qquad \begin{aligned} 10-T_{2} &=2 \times \dfrac{5}{3} \\ T_{2} &=10-\dfrac{10}{3} \\ T_{2} &=10 \times \dfrac{2}{3} \\ T_{2} &=\dfrac{20}{3} N \end{aligned} \end{array} $$

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Physics

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