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Question

In the arrangement shown in the figure, there is friction force between the blocks of masses $$m$$ and $$2m$$, Block of mass $$2m$$ is kept on a smooth horizontal place. The mass of the suspended block is $$m$$. If block $$A$$ is stationary with respect to block of mass $$2m$$. The minimum value of coefficient of friction between $$m$$ and $$2m$$ is
1122406_554d428cb98b4a53877530bd3a691e77.png


A
1/2
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B
1/2
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C
1/4
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D
1/3
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Solution

The correct option is C 1/4
$$ \begin{array}{l} \text { Correct option is }(c) \\ \text { For } c \Rightarrow m g-T=m a---(1) \\ \text { For } A, B(\text { system }) \Rightarrow \\ \text { putting in } e q \text { . (1) } \\ \qquad g / 4=a \end{array} $$


$$ \text { on } \begin{aligned} A ; \quad f &=m a \\ \mu N &=m(g / 4) \\ \mu m g &=m(q / 4) \\ \mu &=1 / 4 \end{aligned} $$

Physics

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