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Question

In the binomial (21/3+3−1/3)n if the ratio of the seventh term from the beginning of the expansion to the seventh term from its end is 1/6 then n is equal to

A
6
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B
9
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C
12
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D
15
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Solution

The correct option is B 9
From the above question we can conclude
6T7=Tn7
Hence
nC62n63.32.6=nC636n3.22
Hence
(2.3)n63.6=(2.3)2
Hence
6n63=626=61
Comparing the indices, we get
n6=3
n=9.

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