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Question

In the binomial expansion of (32+133)n, the ratio of the 7th term from the beginning to the 7th term from the end is 1:6. Find n.

A
9
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B
7
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C
5
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D
3
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Solution

The correct option is D 9
(32+133)n

Here a=32 b=133

We have the general form for term in binomial expression,

Tr+1= nrC anr br

Given, 7th term from beginning7th term from the end=16

n6C (213)n6.(1313)6 nn6C (213)6.(1313)n6=16

(213)n12(1313)n12=16

2n123× 3n123=16

6n123=61

n12=3

n=9

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